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42x=-3x^2-144
We move all terms to the left:
42x-(-3x^2-144)=0
We get rid of parentheses
3x^2+42x+144=0
a = 3; b = 42; c = +144;
Δ = b2-4ac
Δ = 422-4·3·144
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-6}{2*3}=\frac{-48}{6} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+6}{2*3}=\frac{-36}{6} =-6 $
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